The titration of 25.0 mL of an unknown concentration H₂SO₄ solution requires 83.6 mL of a 0.12 mol L^-1 LiOH solution. What is the concentration of the H₂SO₄ solution (in mol L^-1)? A) 0.20 mol L^-1 B) 0.40 mol L^-1 C) 0.10 mol L^-1 D) 0.36 mol L^-1 E) 0.25 mol L^-1

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is:H₂SO₄ + 2LiOH → Li₂SO₄ + 2H₂OFrom the equation, we can see that 1 mole of H₂SO₄ reacts with 2 moles of LiOH. Therefore, the number of moles of H₂SO₄ in the 25.0 mL sample is:(83.6 mL LiOH solution) × (0.12 mol LiOH/L) × (1 mol H₂SO₄/2 mol LiOH) = 0.00502 mol H₂SO₄The concentration of the H₂SO₄ solution is therefore:(0.00502 mol H₂SO₄) / (0.0250 L) = 0.20 mol L^-1

The Titration of 25