Refer to Diagram 9-1.According to molecular orbital theory,which of the following species will have the highest bond order? A) H₂- B) Li₂ C) C₂+ D) N₂ E) H₂

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The bond order in molecular orbital theory is calculated as (bonding electrons - antibonding electrons)/2. The species with the highest bond order will have the greatest difference between the number of bonding and antibonding electrons, indicating a stronger bond. Without the specific details from Diagram 9-1, we rely on general knowledge that N2 (which D seems to represent if we correct the notation to N2) has a triple bond in its diatomic form, indicating a high bond order, typically higher than that of other diatomic molecules formed by elements in similar periods.