Cesium crystallizes in the body-centered cubic system.If the edge of the unit cell is 612 pm,what is the radius of a cesium atom in picometers?
A) 265 pm
B) 1060 pm
C) 1410 pm
D) 1220 pm
E) 115 pm

Question

Quizplus · Accepted Answer

In a body-centered cubic (bcc) system, the diagonal across the body of the cube is equal to four times the radius of the atom (4r). This diagonal can also be calculated using the Pythagorean theorem in three dimensions as √3 times the edge length (a). Therefore, √3a = 4r. Given that the edge length (a) is 612 pm, we can solve for r: r = (612 pm * √3) / 4 = 265 pm.

Cesium Crystallizes in the Body-Centered Cubic System