What volume of a 0.758 M solution of CaCl₂ contains 1.28 g of solute? A) 65.7 mL B) 15.2 mL C) 1.69 mL D) 8.74 mL E) 84.8 mL

Question

Quizplus · Accepted Answer

To find the volume of solution that contains 1.28 g of CaCl2, first calculate the molar mass of CaCl2. Calcium (Ca) has a molar mass of 40.08 g/mol, and chlorine (Cl) has a molar mass of 35.45 g/mol. Therefore, the molar mass of CaCl2 is 40.08 g/mol + 2(35.45 g/mol) = 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 1.28 g: moles = mass / molar mass = 1.28 g / 110.98 g/mol ≈ 0.0115 mol. Finally, use the molarity equation, M = moles / L, to find the volume in liters and then convert to milliliters: volume = moles / M = 0.0115 mol / 0.758 mol/L ≈ 0.0152 L = 15.2 mL.

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