Which of the following is correct for the condensation of gaseous oxygen at -188 °C? (The normal boiling point of oxygen is -183 °C.) A) ΔH 0,and ΔG 0. B) ΔH 0,ΔS 0.

Question

Which of the following is correct for the condensation of gaseous oxygen at -188 °C? (The normal boiling point of oxygen is -183 °C.) A) ΔH < 0,ΔS > 0,and ΔG > 0. B) ΔH < 0,ΔS < 0,and ΔG >0. C) ΔH > 0,ΔS < 0,and ΔG < 0. D) ΔH = 0,ΔS = 0,and ΔG < 0. E) ΔH > 0,ΔS > 0,and ΔG > 0.

Quizplus · Accepted Answer

Condensation is an exothermic process (releases heat), so ΔH < 0. It involves a gas becoming a liquid, which decreases the system's entropy (ΔS < 0). Since the process is spontaneous at -188 °C (below the boiling point), ΔG must be < 0, not > 0. Therefore, the correct statement should indicate ΔH < 0, ΔS < 0, and ΔG < 0, but none of the options correctly states ΔG < 0 for a spontaneous process. Given the options, B is the closest to being correct, acknowledging an error in the explanation regarding ΔG's sign based on the provided choices.

Which of the Following Is Correct for the Condensation of Gaseous