Given the Following Reduction Potentials, NAD⁺ + H⁺ + 2e−

Given the following reduction potentials, NAD⁺ + H⁺ + 2e− → NADH
Ε° = −0.105 V
2H⁺ + 2e⁻ → H₂
Ε° = 0.000 V
Calculate the standard reduction potential and identify the reducing agent in the following reaction.
NAD⁺ + H₂ → NADH + 2H⁺

A) 0.105 V,NAD⁺
B) −0.105 V,NAD⁺
C) −0.105 V,H₂
D) 0.105 V,H₂
E) −0.105 V,NADH