In a population that is in Hardy-Weinberg equilibrium, the frequency of the homozygous dominant genotype is 0.49. The percentage of the population that is heterozygous is ____.
A)51
B)49
C)42
D)7
E)3

Question

Quizplus · Accepted Answer

The frequency of the homozygous dominant genotype (AA) is 0.49, so p² = 0.49. If we take the square root of both sides, we get p = 0.7.

Since p + q = 1 (where q represents the frequency of the recessive allele), we can solve for q:

q = 1 - p = 1 - 0.7 = 0.3.

To calculate the frequency of the heterozygous genotype (Aa), we multiply p and q and double the result:

2pq = 2 x 0.7 x 0.3 = 0.42 or 42%.

Therefore, the answer is C: 42.

In a Population That Is in Hardy-Weinberg Equilibrium, the Frequency