According to Valence Bond theory, in the square planar Ni(CN)₄^2- complex ion, the orbital hybridization pattern is A)sp³. B)dsp². C)d²sp. D)d²sp³. E) None of these choices are correct.

Question

Quizplus · Accepted Answer

In square planar geometry, the hybridization of the metal center is dsp2. This means that there are 5 hybrid orbitals formed from the 3d, 4s, and 4p orbitals of the Ni atom, which are used to form 5 sigma bonds with the surrounding ligands. The remaining 4 orbitals are filled with electrons to complete the octet of the Ni atom. Therefore, the hybridization pattern in the Ni(CN)₄^2- complex ion is dsp².

According to Valence Bond Theory, in the Square Planar Ni(CN)42-

According to Valence Bond Theory, in the Square Planar Ni(CN)₄^2-