Excited sodium atoms emit light in the infrared at 589 nm.What is the energy of a single photon with this wavelength?

Question

Quizplus · Accepted Answer

The energy of a photon can be calculated using the equation $E = \frac{hc}{\lambda}$, where $h$ is Planck's constant ($6.626 \times 10^{-34} \text{ m}^2\text{kg/s}$), $c$ is the speed of light ($3.00 \times 10^8 \text{ m/s}$), and $\lambda$ is the wavelength of the light (589 nm or $589 \times 10^{-9} \text{ m}$). Substituting these values into the equation gives an energy of approximately $3.37 \times 10^{-19} \text{ J}$, which corresponds to choice C.

Excited Sodium Atoms Emit Light in the Infrared at 589