A natural product was isolated in the laboratory,and its observed rotation was +10° when measured in a 1 dm sample tube containing 1.0 g of compound in 10 mL of H₂O.What is the specific rotation of this compound? A)-10° B)+100° C)+10° D)-100°

Question

Quizplus · Accepted Answer

The specific rotation $[α]$ is calculated using the formula $[α] = \frac{α}{l \times c}$, where $α$ is the observed rotation, $l$ is the path length in decimeters, and $c$ is the concentration in grams per milliliter. Plugging in the given values, $[α] = \frac{+10°}{1 \times 0.1} = +100°$.

A Natural Product Was Isolated in the Laboratory,and Its Observed