A cross is made between two parents with genotypes AaBB and aabb. If there are 32 offspring, how many of them would be expected to exhibit both dominant characteristics?
A) 32
B) 24
C) 16
D) 8
E) 0

Question

Quizplus · Accepted Answer

The dominant characteristics are represented by the alleles A and B. 
The possible gametes for parent 1 (AaBB) are AB and aB.
The possible gametes for parent 2 (aabb) are ab.

The Punnett square for the cross would be:

| A  | a
--|---|--
B | AB | aB
b | Ab | ab

The offspring genotypes and phenotypes would be:

- 25% AaBB (dominant for A and B)
- 25% Aabb (dominant for A)
- 25% aaBB (dominant for B)
- 25% aabb (no dominant characteristics)

Thus, the number of offspring with both dominant characteristics (A and B) would be 25% of 32, which is 8. Therefore, the answer is C.

A Cross Is Made Between Two Parents with Genotypes AaBB