The weights of a sample of crates ready for shipment to Moscow, Russia are (in kilograms): 103, 97, 101, 106 and 103. What is the mean deviation?
A) 0 kg
B) 6.9 kg
C) 102.0 kg
D) 2.4 kg
E) 9.0 kg

Question

Quizplus · Accepted Answer

To find the mean deviation, we need to first find the mean of the weights:
(103 + 97 + 101 + 106 + 103) / 5 = 102 kg
Next, we need to find the deviation of each data point from the mean:
|103-102| = 1
|97-102| = 5
|101-102| = 1
|106-102| = 4
|103-102| = 1
Then we find the mean of these deviations:
(1+5+1+4+1)/5 = 2.4 kg
Therefore, the mean deviation is 2.4 kg, which is option D.

The Weights of a Sample of Crates Ready for Shipment