Every spring semester,the School of Business coordinates with local business leaders a luncheon for graduating seniors,their families,and friends.Corporate sponsorship pays for the lunches of each of the seniors,but students have to purchase tickets to cover the cost of lunches served to guests they bring with them.Data on the number of guests each graduating senior invited to the luncheon from 500 graduating seniors last year were collected.Based on this information,which of the following will you construct to learn about the percentage of seniors who will bring at least one guest to the luncheon?
A)Confidence interval estimate for the total using the Student's t distribution
B)Confidence interval estimate for the mean using the Student's t distribution
C)Confidence interval estimate for the proportion using the standard normal distribution
D)Confidence interval estimate for the difference between two means using the standard normal distribution

Question

Quizplus · Accepted Answer

Since we want to learn about the percentage of seniors who will bring at least one guest, which is a proportion, we need to construct a confidence interval estimate for the proportion. This can be done using the standard normal distribution since the sample size is large enough (500 graduating seniors). Therefore, choice C is the best option. Choices A and B are incorrect since they are used when constructing confidence intervals for means. Choice D is not applicable in this scenario since there are no two means being compared.

Every Spring Semester,the School of Business Coordinates with Local Business