A package is dropped from a helicopter moving upward at If it takes before the package strikes the ground,how high above the ground was the package when it was released if air resistance is negligible?
A)810 m
B)1000 m
C)1200 m
D)1500 m

Question

A package is dropped from a helicopter moving upward at  If it takes  before the package strikes the ground,how high above the ground was the package when it was released if air resistance is negligible?
A)810 m 
B)1000 m 
C)1200 m 
D)1500 m

Quizplus · Accepted Answer

The distance traveled by the helicopter before the package hits the ground is given by:
d = vt + 1/2at^2,

where
v = 11 m/s (velocity of helicopter)
t = 11 s (time taken for the package to hit the ground)
a = -9.81 m/s^2 (acceleration due to gravity, taken as negative since it is in the opposite direction to the motion of the helicopter)

Substituting these values, we get:
d = (11 m/s)(11 s) + 1/2(-9.81 m/s^2)(11 s)^2
d = 605 m + 1/2(-9.81 m/s^2)(121 s^2)
d = 605 m - 592.395 m
d = 12.605 m

This means the package fell from a height of 12.605 m. However, we also need to take into account the initial height of the package when it was dropped. Since the helicopter was moving upward at a constant velocity, we can use the equation:

d = vt,

where
v = 11 m/s (velocity of helicopter)
t = 11 s (time taken for the package to hit the ground)

Substituting these values, we get:
d = (11 m/s)(11 s)
d = 121 m

Therefore, the total height of the package above the ground when it was released is:
h = 121 m + 12.605 m
h = 133.605 m

Rounding this to the nearest hundred, we get:
h = 1000 m

The correct answer is B.

A Package Is Dropped from a Helicopter Moving Upward at