A rope pulls on the lower block in the figure with a tension force of 20 N.The coefficient of kinetic friction between the lower block and the surface is 0.16.The coefficient of kinetic friction between the lower block and the upper block is also 0.16.The pulley has no appreciable mass or friction.What is the acceleration of the 2.0 kg block? A)4.1 m/s² B)5.1 m/s² C)8.4 m/s² D)9.2 m/s²

Question

Quizplus · Accepted Answer

First, we need to calculate the net force acting on the 2.0 kg block.
Net force = tension force - frictional force
Frictional force = coefficient of kinetic friction x normal force
Normal force = force due to gravity = mass x gravity
Frictional force = 0.16 x (2.0 kg x 9.81 m/s^2) = 3.13 N
Normal force on lower block = 2.0 kg x 9.81 m/s^2 = 19.62 N
Net force = 20 N - 3.13 N = 16.87 N
Now, we can use Newton's second law to find the acceleration of the block:
Net force = mass x acceleration
16.87 N = 2.0 kg x acceleration
Acceleration = 8.435 m/s^2
Since the upper block is not moving, the acceleration of the lower block is also the acceleration of the system.
Therefore, the correct answer is A) 4.1 m/s^2.

A Rope Pulls on the Lower Block in the Figure