A very light 1.00-m wire consists of two segments of equal length,one of steel (Young's modulus is 2.00 × 10¹¹ N/m²)and one of brass (Young's modulus is 9.0 × 10¹⁰ N/m²).The steel segment is 1.50 mm in diameter,and the brass segment has twice this diameter.When a weight w is hung from the ceiling by this wire,the steel segment stretches by 1.10 mm.Find the weight w. A)190 N B)390 N C)780 N D)1000 N E)3100 N

Question

Quizplus · Accepted Answer

The weight w causes a stretch in the steel segment, which can be calculated using the formula for elongation: ΔL = (F * L) / (A * Y), where F is the force (weight), L is the original length, A is the cross-sectional area, and Y is Young's modulus. Solving for F using the given values for the steel segment, we find that w = 780 N.

A Very Light 1