What is wrong with the following code fragment?
Int *p1, *p2;
P1 = new int;
P2 = new int;
*p1=11;
*p2=0;
P2=p1;
Cout

Question

What is wrong with the following code fragment?
Int *p1, *p2;
P1 = new int;
P2 = new int;
*p1=11;
*p2=0;
P2=p1;
Cout << *p1 <<" " << *p2 << endl;
Delete p1;
Delete p2;
A) nothing
B) p1 and p2 both have the same value, so the delete p2 will cause an error
C) You have a memory leak.
D) B and C

Quizplus · Accepted Answer

The pointers p1 and p2 are both initialized using the 'new' operator. The first problem is that p2 is immediately assigned the value of p1, which means the memory that was allocated for p2 is now leaked. Secondly, when we try to delete the memory pointed to by p2, we are actually trying to delete the same memory that is pointed by p1 since p2 was assigned the value of p1. So, this causes undefined behavior and may result in a runtime error. Hence, the correct answer is D.

What Is Wrong with the Following Code Fragment