A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field = 0.30 T
. The normal to the loop is parallel to a unit vector
= -0.60
- 0.80
. Calculate the magnitude of the torque on the loop due to the magnetic field.

Question

A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field

= 0.30 T

. The normal to the loop is parallel to a unit vector A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field = 0.30 T . The normal to the loop is parallel to a unit vector = -0.60 - 0.80 . Calculate the magnitude of the torque on the loop due to the magnetic field. A) 4.7 × 10-4 N ∙ m B) 2.8 × 10-4 N ∙ m C) 0.60 × 10-4 N ∙ m D) 1.2 × 10-4 N ∙ m E) zero

= -0.60

- 0.80

. Calculate the magnitude of the torque on the loop due to the magnetic field.

Quizplus · Accepted Answer

The Answer of A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field = 0.30 T . The normal to the loop is parallel to a unit vector = -0.60 - 0.80 . Calculate the magnitude of the torque on the loop due to the magnetic field. A) 4.7 × 10^-4 N ∙ m B) 2.8 × 10^-4 N ∙ m C) 0.60 × 10^-4 N ∙ m D) 1.2 × 10^-4 N ∙ m E) zero

A Circular Loop of Diameter 10 Cm, Carrying a Current