Choose the reagents to make the conversion from I to II. A) NaH B) LiAlD₄ C) NaBH₄ D) H₃O⁺ E) All of the above.

Question

Quizplus · Accepted Answer

The conversion from I to II involves reduction of the carbonyl group to a methylene group. This can be achieved using a reducing agent such as NaBH4 or LiAlH4. Of the given options, only (C) NaBH4 is a suitable reducing agent for this transformation. NaH is a strong base and would not have a reducing effect on the carbonyl group. LiAlH4 is too strong of a reducing agent and would lead to over-reduction of the molecule, leading to the formation of a primary alcohol. Option (D) is not a real reagent. Therefore, (C) NaBH4 is the best choice for this conversion.

Choose the Reagents to Make the Conversion from I to II