Describe the number of signals and their splitting in the ¹H NMR spectrum of (CH₃)₂CHOCH₃. A) 3 signals: 2 doublets and a septet B) 2 signals: a doublet and a septet C) 3 signals: a doublet, a quartet, and a septet D) 4 signals: 2 doublets, a singlet, and a septet E) 3 signals: a singlet, a doublet, and a septet

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The compound given is (CH3)2CHOCH3. In its NMR spectrum, the methyl groups (CH3) attached to the carbon bearing the hydroxyl group (OH) are equivalent and give rise to a singlet due to the lack of neighboring hydrogens to split their signal. The methyl group (CH3) attached to the carbonyl (C=O) is also in a unique environment but does not have neighboring hydrogens to split its signal, resulting in another singlet. However, since both methyl groups attached to the carbon bearing the hydroxyl group are equivalent, they are represented as one signal, leading to a misunderstanding in the explanation. The correct analysis should consider the unique environments of the hydrogens: the methyl groups (CH3) attached to the same carbon (in this case, the carbon bearing the hydroxyl group) are equivalent and produce one signal, the methyl group (CH3) attached to the carbonyl (C=O) produces another signal, and the hydrogen on the hydroxyl group (OH) produces a third signal. The splitting patterns arise from the interactions between these hydrogens and their neighbors, but given the structure, the correct interpretation involves recognizing the distinct environments of the hydrogens rather than focusing solely on the presence of singlets.

Describe the Number of Signals and Their Splitting in the 1H

Describe the Number of Signals and Their Splitting in the ¹H