The pH of a 150 mL aqueous solution of 2.13 x 10^-3 M HCl is ________. A) -3.000 B) 3.000 C) 2.672 D) 2.130 E) none of the above

Question

Quizplus · Accepted Answer

The pH of a solution can be calculated using the formula:

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in the solution.

In this case, the concentration of HCl is given as 2.13 x 10^-3 M. Since HCl is a strong acid, it completely dissociates in water to give H+ and Cl- ions. Therefore, the concentration of H+ ions is also 2.13 x 10^-3 M.

Substituting this value into the pH formula,

pH = -log(2.13 x 10^-3)

Using a calculator, this gives a pH of 2.672.

Therefore, the answer is C) 2.672.

The PH of a 150 ML Aqueous Solution of 2