Decide what values of the variable cannot possibly be solutions for the equation.
-$$\frac { - 5 } { x - 2 } + \frac { 2 } { x + 2 } = \frac { - 20 } { x ^ { 2 } - 4 }$$
A) $\{ 2 \}$
B) $\{ - 2 \}$
C) $\varnothing$
D) $\left\{ \frac { 8 } { 3 } \right\}$

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The Answer of Decide what values of the variable cannot possibly be solutions for the equation.
-$$\frac { - 5 } { x - 2 } + \frac { 2 } { x + 2 } = \frac { - 20 } { x ^ { 2 } - 4 }$$
A) $\{ 2 \}$
B) $\{ - 2 \}$
C) $\varnothing$
D) $\left\{ \frac { 8 } { 3 } \right\}$

Decide What Values of the Variable Cannot Possibly Be Solutions −5x−2+2x+2=−20x2−4\frac { - 5 } { x - 2 } + \frac { 2 } { x + 2 } = \frac { - 20 } { x ^ { 2 } - 4 }x−2−5​+x+22​=x2−4−20​

Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { - 5 } { x - 2 } + \frac { 2 } { x + 2 } = \frac { - 20 } { x ^ { 2 } - 4 }$