Decide what values of the variable cannot possibly be solutions for the equation.
-$$\frac { 4 } { x - 1 } + \frac { 6 x } { 1 - x } = 11$$
A) $- 1,1$
B) $- 1,0,1$
C) 1
D) $- 1,0$

Question

Quizplus · Accepted Answer

The values of the variable that cannot possibly be solutions for the equation are those that make the denominator of any fraction equal to zero. In this equation, the denominators are $x - 1$ and $1 - x$. Setting $x - 1 = 0$ gives $x = 1$, which means $x = 1$ is the value that cannot be a solution because it would make the denominator zero, leading to division by zero, which is undefined.

Decide What Values of the Variable Cannot Possibly Be Solutions 4x−1+6x1−x=11\frac { 4 } { x - 1 } + \frac { 6 x } { 1 - x } = 11x−14​+1−x6x​=11

Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { 4 } { x - 1 } + \frac { 6 x } { 1 - x } = 11$