Decide what values of the variable cannot possibly be solutions for the equation.
-$$\frac { 3 x + 6 } { 3 } - \frac { 4 x } { x - 3 } = x$$
A) $\{ 1 \}$
B) $\{ - 1 \}$
C) $\left\{ - \frac { 3 } { 11 } \right\}$
D) $\{ - 3 \rangle$

Question

Quizplus · Accepted Answer

The value $x = -3$ makes the denominator of the second fraction zero, which is undefined in mathematics. Therefore, $x$ cannot be $-3$.

Decide What Values of the Variable Cannot Possibly Be Solutions 3x+63−4xx−3=x\frac { 3 x + 6 } { 3 } - \frac { 4 x } { x - 3 } = x33x+6​−x−34x​=x

Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { 3 x + 6 } { 3 } - \frac { 4 x } { x - 3 } = x$