You have three ammonium chloride solutions on a lab table in front of you. All of the solutions came from a 500.0-mL volumetric flask containing 3.00 M ammonium chloride. Solution 1 contains 124.6 mL of the 3.00 M solution.
Solution 2 contains 52.9 mL of the 3.00 M solution.
Solution 3 contains 21.3 mL of the 3.00 M solution.
How many moles of ions does Solution 3 contain?
A) 0.128 mol
B) 0.192 mol
C) 0.320 mol
D) 0.0639 mol
E) 0.0320 mol

Question

Quizplus · Accepted Answer

Solution 3 contains 21.3 mL of a 3.00 M ammonium chloride solution. The number of moles of ammonium chloride is calculated as (21.3 mL / 1000 mL/L) * 3.00 mol/L = 0.0639 mol. Since ammonium chloride dissociates into two ions (NH4+ and Cl-), the total moles of ions is 0.0639 mol * 2 = 0.128 mol.

You Have Three Ammonium Chloride Solutions on a Lab Table