If a 74.6-g sample of ammonium nitrate is dissolved in enough water to make 315 mL of solution, what will be the molarity?
A) 0.932 M
B) 2.96 M
C) 0.294 M
D) 3.41 M
E) none of these

Question

Quizplus · Accepted Answer

To find the molarity, first calculate the moles of ammonium nitrate (NH4NO3) using its molar mass (80.04 g/mol). Moles = 74.6 g / 80.04 g/mol = 0.932 moles. Then, convert 315 mL to liters (0.315 L). Molarity = moles/volume = 0.932 moles / 0.315 L = 2.96 M.

If a 746-G Sample of Ammonium Nitrate Is Dissolved in Enough Water