The molarity of Cl^- in 110. mL of a solution containing 3.22 g of CaCl₂ is A) 0.264 M B) 0.0290 M C) 0.00319 M D) 0.528 M E) 0.354 M

Question

Quizplus · Accepted Answer

First, calculate the moles of CaCl2: Molar mass of CaCl2 = 40.08 (Ca) + 2(35.45) (Cl) = 110.98 g/mol. Moles of CaCl2 = 3.22 g / 110.98 g/mol = 0.0290 mol. Since each CaCl2 produces 2 Cl- ions, moles of Cl- = 2 * 0.0290 mol = 0.0580 mol. Molarity of Cl- = 0.0580 mol / 0.110 L = 0.528 M.

The Molarity of Cl- in 110

The Molarity of Cl^- in 110