A 47.7-g sample of SrCl₂ is dissolved in 112.5 mL of solution. Calculate the molarity of this solution. A) 0.301 M B) 2.67 M C) 0.0339 M D) 3.99 M E) none of these

Question

Quizplus · Accepted Answer

To find the molarity, first calculate the moles of SrCl2: Molar mass of SrCl2 = 87.62 (Sr) + 2(35.45) (Cl) = 158.52 g/mol. Moles of SrCl2 = 47.7 g / 158.52 g/mol = 0.3008 mol. Molarity = moles/volume in liters = 0.3008 mol / 0.1125 L = 2.67 M.

A 477-G Sample of SrCl2 Is Dissolved in 112

A 477-G Sample of SrCl₂ Is Dissolved in 112