How many d electrons are there in the octahedral complex ion, Mn(CN)₆^4-? A)1 B)2 C)3 D)4 E)5

Name: How many d electrons are there in the octahedral complex ion, Mn(CN) 6 4- ? A)1 B)2 C)3 D)4 E)5
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Mn in Mn(CN)6^4- has an oxidation state of +2 (since CN^- is a -1 ligand and there are 6 of them, the total charge is -4, making Mn +2 to balance the charge). Mn^2+ has a [Ar]3d^5 electron configuration. In an octahedral complex, all 5 d electrons remain in the d orbitals, so there are 5 d electrons.

How Many D Electrons Are There in the Octahedral Complex