A transition metal complex ion with octahedral geometry has a value of 4.4 $\times$ 10^-19J for the crystal field splitting, $\Delta$_o. What is the wavelength for the absorption maximum, $\lambda$_max, for this complex ion? A)5.0 $\times$ 10^-15 nm B)452 nm C)4.5 $\times$ 10^-16 nm D)524 nm E)637 nm

Question

Quizplus · Accepted Answer

The wavelength for the absorption maximum ($\lambda_{max}$) can be calculated using the equation $\lambda = \frac{hc}{\Delta}$, where $h$ is Planck's constant, $c$ is the speed of light, and $\Delta$ is the crystal field splitting energy. Given that $\Delta = 4.4 \times 10^{-19}$ J, substituting the values for $h$ (6.626 x 10^-34 J s) and $c$ (3.00 x 10^8 m/s) into the equation and solving for $\lambda$ gives a wavelength in meters, which can be converted to nanometers (nm) by multiplying by $10^9$. The result is approximately 452 nm, which corresponds to choice B.

A Transition Metal Complex Ion with Octahedral Geometry Has a Value