Find the area of that part of the plane $2 x + 3 y - z + 1 = 0$ that lies above the rectangle [1, 4] $\times$ [2, 4].

Name: Find the area of that part of the plane $2 x + 3 y - z + 1 = 0$ that lies above the rectangle [1, 4] $\times$ [2, 4].
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The Answer of Find the area of that part of the plane $2 x + 3 y - z + 1 = 0$ that lies above the rectangle [1, 4] $\times$ [2, 4].

Find the Area of That Part of the Plane 2x+3y−z+1=02 x + 3 y - z + 1 = 02x+3y−z+1=0

Find the Area of That Part of the Plane $2 x + 3 y - z + 1 = 0$