Set up, but do not evaluate, the integral to find the surface area of the portion of the sphere $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 16$ between the planes z = 1 and z = 2.

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The Answer of Set up, but do not evaluate, the integral to find the surface area of the portion of the sphere $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 16$ between the planes z = 1 and z = 2.

Set Up, but Do Not Evaluate, the Integral to Find x2+y2+z2=16x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 16x2+y2+z2=16

Set Up, but Do Not Evaluate, the Integral to Find $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 16$