In the previous problem, the solution of the eigenvalue problem is
A) $\lambda = n \pi , T = a _ { n } \cos ( n \pi i ) + b _ { n } \sin ( n \pi t )$
B) $\lambda = n ^ { 2 } \pi ^ { 2 } , T = a _ { n } \cos ( n \pi t ) + b _ { n } \sin ( n \pi t )$
C) $\lambda = z _ { n } ^ { 2 } / 4$ , where $J _ { 0 } \left( z _ { n } \right) = 0 , R = J _ { 0 } \left( z _ { n } r / 2 \right)$
D) $\lambda = z _ { n } / 2$ , where $J _ { 0 } \left( z _ { n } \right) = 0 , R = J _ { 0 } \left( z _ { n } r / 2 \right)$
E) $\lambda = z _ { n } ^ { 2 }$ , where $J _ { 0 } \left( z _ { n } \right) = 0 , R = J _ { 0 } \left( z _ { n } r \right)$

Question

Quizplus · Accepted Answer

The Answer is C

In the Previous Problem, the Solution of the Eigenvalue Problem λ=nπ,T=ancos⁡(nπi)+bnsin⁡(nπt)\lambda = n \pi , T = a _ { n } \cos ( n \pi i ) + b _ { n } \sin ( n \pi t )λ=nπ,T=an​cos(nπi)+bn​sin(nπt)

In the Previous Problem, the Solution of the Eigenvalue Problem $\lambda = n \pi , T = a _ { n } \cos ( n \pi i ) + b _ { n } \sin ( n \pi t )$