Select the correct graph of the polar equation.Describe your viewing window. $$r = \frac { \pi } { 4 }$$
A) $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$
B) $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$
C) $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$
D) $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$
E) $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$

Question

Select the correct graph of the polar equation.Describe your viewing window.​ $$r = \frac { \pi } { 4 }$$ ​
A)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$ 
B)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$ 
C)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$ 
D)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$ 
E)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$

Quizplus · Accepted Answer

The Answer of Select the correct graph of the polar equation.Describe your viewing window.​ $$r = \frac { \pi } { 4 }$$ ​
A)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$ 
B)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$ 
C)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$ 
D)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$ 
E)​ $$\begin{array} { l } \theta _ { \min } = 0 \ \theta _ { \max } = 2 \pi \ \theta _ { s t e p } = \pi / 24 \ X _ { \min } = - 2 \ X _ { \max } = 2 \ X _ { s c l } = 0.5 \ Y _ { \min } = - 2 \ Y _ { \max } = 2 \ Y _ { s c l } = 0.5 \end{array}$$

Select the Correct Graph of the Polar Equation r=π4r = \frac { \pi } { 4 }r=4π​

Select the Correct Graph of the Polar Equation $r = \frac { \pi } { 4 }$