Find the domain of the function. $g ( p ) = \sqrt { 81 - p ^ { 2 } }$
A)-9 ? p ?9
B)p ? -9 or p? 9
C)p ? 0
D)p ? 9
E)all real numbers

Question

Quizplus · Accepted Answer

The domain of $g(p) = \sqrt{81 - p^2}$ includes all values of $p$ for which the expression under the square root, $81 - p^2$, is greater than or equal to 0. Solving the inequality $81 - p^2 ≥ 0$ leads to $(-9 ≤ p ≤ 9)$, which means the function is defined for all $p$ in the interval $[-9, 9]$.

Find the Domain of the Function g(p)=81−p2g ( p ) = \sqrt { 81 - p ^ { 2 } }g(p)=81−p2​

Find the Domain of the Function $g ( p ) = \sqrt { 81 - p ^ { 2 } }$