Find the difference quotient and simplify your answer. F(y)= 6y² - 3y, $\frac { f ( 2 + h ) - f ( 2 ) } { h }$ ,h ? 0 A) $\frac { f ( 2 + h ) - f ( 2 ) } { h } = 21 + 6 h$ B) $\frac { f ( 2 + h ) - f ( 2 ) } { h } = - 3 + 6 y - \frac { 12 } { y }$ C) $\frac { f ( 2 + h ) - f ( 2 ) } { h } = - 3 + 6 h$ D) $\frac { f ( 2 + h ) - f ( 2 ) } { h } = 21 + 6 y - \frac { 12 } { y }$ E) $\frac { f ( 2 + h ) - f ( 2 ) } { h } = 1 + h$

Question

Quizplus · Accepted Answer

First, substitute $y = 2 + h$ and $y = 2$ into the function $F(y) = 6y^2 - 3y$, then find the difference quotient. Simplifying the expression yields $21 + 6h$.

Find the Difference Quotient and Simplify Your Answer f(2+h)−f(2)h\frac { f ( 2 + h ) - f ( 2 ) } { h }hf(2+h)−f(2)​

Find the Difference Quotient and Simplify Your Answer $\frac { f ( 2 + h ) - f ( 2 ) } { h }$