Find $f \circ g$ . $f ( x ) = x + 3 \quad g ( x ) = \frac { 1 } { x ^ { 2 } - 9 }$
A) $( f \circ g ) ( x ) = \frac { 1 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 4 } { x ^ { 2 } - 9 }$
C) $( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } - 2 } { x ^ { 2 } - 9 }$
D) $( f \circ g ) ( x ) = \frac { 1 } { x ^ { 2 } + 6 x }$
E) $( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } - 26 } { x ^ { 2 } - 9 }$

Question

Find $f \circ g$ .​ $f ( x ) = x + 3 \quad g ( x ) = \frac { 1 } { x ^ { 2 } - 9 }$ ​
A) $( f \circ g ) ( x ) = \frac { 1 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 4 } { x ^ { 2 } - 9 }$
C) $( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } - 2 } { x ^ { 2 } - 9 }$
D) $( f \circ g ) ( x ) = \frac { 1 } { x ^ { 2 } + 6 x }$
E) $( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } - 26 } { x ^ { 2 } - 9 }$

Quizplus · Accepted Answer

The Answer of Find $f \circ g$ .​ $f ( x ) = x + 3 \quad g ( x ) = \frac { 1 } { x ^ { 2 } - 9 }$ ​
A) $( f \circ g ) ( x ) = \frac { 1 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 4 } { x ^ { 2 } - 9 }$
C) $( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } - 2 } { x ^ { 2 } - 9 }$
D) $( f \circ g ) ( x ) = \frac { 1 } { x ^ { 2 } + 6 x }$
E) $( f \circ g ) ( x ) = \frac { 3 x ^ { 2 } - 26 } { x ^ { 2 } - 9 }$

Find f∘gf \circ gf∘g ​ f(x)=x+3g(x)=1x2−9f ( x ) = x + 3 \quad g ( x ) = \frac { 1 } { x ^ { 2 } - 9 }f(x)=x+3g(x)=x2−91​

Find $f \circ g$ $f ( x ) = x + 3 \quad g ( x ) = \frac { 1 } { x ^ { 2 } - 9 }$