The Designers of a Water Park Are Creating a New $\theta$

The designers of a water park are creating a new slide and have sketched some preliminary drawings.The length of the ladder is a = 26 feet,and its angle of elevation is 60º (see figure) .? ?
Find the angle of depression $\theta$ from the top of the slide to the end of the slide at the ground in terms of the horizontal distance d the rider travels.
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A) $\theta = \arctan \left( \frac { 22.52 } { d } \right)$
B) $\theta = \arctan \left( \frac { 23.52 } { d } \right)$
C) $\theta = \arctan \left( \frac { 24.52 } { d } \right)$
D) $\theta = \arctan \left( \frac { 25.52 } { d } \right)$
E) $\theta = \arctan \left( \frac { 26.52 } { d } \right)$