For the simple harmonic motion described by the trigonometric function,find the least positive value of t for which d = 0.? $$d = \frac { 1 } { 12 } \sin 14 \pi t$$ ?
A) $\frac { 1 } { 14 }$
B) $\frac { 1 } { 12 }$
C) $12$
D) $\frac { 1 } { 6 }$
E) $14$

Question

Quizplus · Accepted Answer

For $d = 0$, the sine function must be zero. The sine function is zero at $t = 0, \frac{1}{14}, \frac{2}{14}, \frac{3}{14}, \ldots$. The least positive value of $t$ that satisfies this condition is $\frac{1}{14}$.

For the Simple Harmonic Motion Described by the Trigonometric Function,find d=112sin⁡14πtd = \frac { 1 } { 12 } \sin 14 \pi td=121​sin14πt

For the Simple Harmonic Motion Described by the Trigonometric Function,find $d = \frac { 1 } { 12 } \sin 14 \pi t$