Use the product-to-sum formulas to rewrite the product as a sum or difference. $$\sin \frac { \pi } { 3 } \cos \frac { \pi } { 6 }$$
A) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$
B) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \sin \frac { \pi } { 6 } \right)$
C) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \cos \frac { \pi } { 6 } \right)$
D) $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \sin \frac { \pi } { 6 } \right)$
E) $\left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$

Question

Use the product-to-sum formulas to rewrite the product as a sum or difference.​ $$\sin \frac { \pi } { 3 } \cos \frac { \pi } { 6 }$$ ​
A)​ $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$
B)​ $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } + \sin \frac { \pi } { 6 } \right)$
C)​ $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \cos \frac { \pi } { 6 } \right)$
D)​ $\frac { 1 } { 2 } \left( \sin \frac { \pi } { 2 } - \sin \frac { \pi } { 6 } \right)$
E)​ $\left( \sin \frac { \pi } { 2 } + \cos \frac { \pi } { 6 } \right)$

Quizplus · Accepted Answer

The Answer is B

Use the Product-To-Sum Formulas to Rewrite the Product as a Sum