John throws a rock down with speed 11 m/s from the top of a 25-m tower.If g = 9.8 m/s² and air resistance is negligible,what is the rock's speed just as it hits the ground? A)19 m/s B)25 m/s C)610 m/s D)22 m/s E)12 m/s

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Quizplus · Accepted Answer

The rock's final speed can be calculated using the equation $v = \sqrt{v_0^2 + 2gh}$, where $v_0 = 11$ m/s (initial speed), $g = 9.8$ m/s$^2$ (acceleration due to gravity), and $h = 25$ m (height). Plugging in the values, we get $v = \sqrt{11^2 + 2 \cdot 9.8 \cdot 25} = \sqrt{121 + 490} = \sqrt{611}$, which is approximately 25 m/s.

John Throws a Rock Down with Speed 11 M/s from the Top