A rock is thrown straight down with an initial velocity of 14.3 m/s from a cliff.What is the rock's displacement after 2.0 s? (Acceleration due to gravity is 9.80 m/s². ) A)81 m B)48 m C)38 m D)22 m E)31 m

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Quizplus · Accepted Answer

The displacement can be calculated using the formula: $ s = ut + \frac{1}{2}at^2 $, where $ u = 14.3 \, \text{m/s} $, $ a = 9.8 \, \text{m/s}^2 $, and $ t = 2.0 \, \text{s} $. Substituting these values gives $ s = 14.3 \times 2 + 0.5 \times 9.8 \times 2^2 = 28.6 + 19.6 = 48.2 \, \text{m} $, which rounds to 48 m.

A Rock Is Thrown Straight Down with an Initial Velocity