Question 1

Match the following. -0 A)number of unpaired electrons in Zn²⁺ B)number of unpaired electrons in Ti²⁺

Accepted Answer

Zn has a d10 configuration and S has a p4 configuration. The electron configuration of ZnS will be [Ar] 3d10 4s2 4p4. As all the electrons are paired, there are 0 unpaired electrons in ZnS.

Answer: B
 
Ti has a d2 configuration and S has a p4 configuration. The electron configuration of TiS will be [Ar] 3d2 4s2 4p4. As there are 2 unpaired electrons in Ti’s d orbital, there are 2 unpaired electrons in TiS.

Question 2

The complete electron configuration of argon, element 18, is ________. A)1s²2s²2p⁶3s²3p⁶ B)1s²2s²2p¹⁰3s²3p² C)1s⁴2s⁴2p⁶3s⁴ D)1s⁴2s⁴2p¹⁰ E)1s⁶2s⁶2p²3s⁴

Accepted Answer

Argon has 18 electrons, and the correct electron configuration is 1s² 2s² 2p⁶ 3s² 3p⁶, which matches choice A.

Question 3

Match the following.

-n = 1 to n = 2
A)657 nm
B)7460 nm
C)103 nm
D)1280 nm
E)122 nm

Accepted Answer

The transition from n=1 to n=2 in a hydrogen atom corresponds to the Lyman series, which involves ultraviolet light. The wavelength for this transition is approximately 122 nm.

Question 4

How many subshells are there in the shell with n = 4?
A)3
B)4
C)6
D)18

Accepted Answer

The number of subshells in a shell can be found using the formula 2n^2. Thus, for n=4, there are 2(4)^2 = 32 electrons and 4 subshells (s,p,d, and f). Therefore, the answer is B.

Question 5

Which ion does not have a noble gas configuration in its ground state? A)Sc³⁺ B)Al³⁺ C)Ga³⁺ D)As^3-

Accepted Answer

The answer of Which ion does not have a noble...

Question 6

Match the following.

-n = 3 to n = 1
A)657 nm
B)7460 nm
C)103 nm
D)1280 nm
E)122 nm

Accepted Answer

The transition from n=3 to n=1 in a hydrogen atom corresponds to the Lyman series, which is in the ultraviolet region. The wavelength for this transition is approximately 103 nm.

Question 7

Define diffraction.

Accepted Answer

The answer of Define diffraction....

Question 8

The element that corresponds to the electron configuration 1s²2s²2p⁶ is ________. A)sodium B)magnesium C)lithium D)beryllium E)neon

Accepted Answer

The electron configuration given corresponds to the noble gas neon (1s2 2s2 2p6). All of the other answer choices have valence electron configurations different from what is given in the question.

Question 9

The de Broglie wavelength of an electron with a velocity of 6.00 × 10⁶ m s^-1 is ________ m. The mass of the electron is 9.11 × 10^-28 g. A)8.25 × 10⁹ B)8.25 × 10¹² C)1.21 × 10^-16 D)1.21 × 10^-13 E)1.21 × 10^-10

Accepted Answer

The de Broglie wavelength λ is calculated using the formula λ = h / (mv), where h is Planck's constant (6.626 × 10^-34 Js), m is the mass of the electron (9.11 × 10^-31 kg), and v is the velocity (6.00 × 10^6 m/s). Converting the mass from grams to kilograms and substituting the values gives λ ≈ 1.21 × 10^-10 m.

Question 10

How many orbitals are there in the fourth shell?
A)3
B)4
C)6
D)16

Accepted Answer

The fourth shell (n=4) has four types of orbitals: s, p, d, and f, with 1, 3, 5, and 7 orbitals respectively, totaling 16 orbitals.

Question 11

The complete electron configuration of gallium, element 31, is ________. A)1s²2s²2p¹⁰3s²3p¹⁰4s²3d³ B)1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p¹ C)1s⁴2s⁴2p⁶3s⁴3p⁶4s⁴3d³ D)1s⁴2s⁴2p¹⁰3s⁴3p⁹ E)1s⁴2s⁴2p⁸3s⁴3p⁸4s³

Accepted Answer

The electron configuration of gallium can be written as follows: 
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1
This can also be abbreviated using the noble gas notation as:
[Ar] 3d10 4s2 4p1
Therefore, the correct electron configuration option would be B, which correctly shows the filling of the energy levels for a gallium atom.

Question 12

What are the possible values of n and m_l for an electron in a 4d orbital? A)n = 1, 2, 3, or 4 and m_l = 2 B)n = 1, 2, 3, or 4 and m_l = -2, -1, 0, +1, or +2 C)n = 4 and m_l = 2 D)n = 5 and m_l = -2, -1, 0, +1, +2

Accepted Answer

The answer of What are the possible values of n...

Question 13

For a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy?
A)2s → 3p
B)2p → 6d
C)6p → 4s
D)7f → 5d

Accepted Answer

The answer of For a hydrogen atom, which electronic transition...

Question 14

For hydrogen, what is the wavelength of the photon emitted when an electron drops from a 4d orbital to a 2p orbital in a hydrogen atom? The Rydberg constant is 1.097 × 10^-2 nm^-1. A)656.3 nm B)486.2 nm C)364.6 nm D)2.057 × 10^-3 nm

Accepted Answer

The wavelength of the photon emitted can be calculated using the Rydberg formula: $ \frac{1}{\lambda} = R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) $, where $ \lambda $ is the wavelength, $ R $ is the Rydberg constant, $ n_1 $ is the lower energy level, and $ n_2 $ is the higher energy level. For a transition from 4d to 2p in hydrogen, $ n_1 = 2 $ and $ n_2 = 4 $. Plugging these values into the formula gives a wavelength that corresponds to the value in choice B, 486.2 nm.

Question 15

What are the possible values of l if n = 6?
A)6
B)0, 1, 2, 3, 4, or 5
C)-4, -3, -2, -1, 0, +1, +2, +3, or +4
D)-5, -4, -3, -2, -1, 0, +1, +2, +3, +4, or +5

Accepted Answer

The possible values of l are all integers from 0 to n-1. 
Therefore, when n = 6, the possible values of l are 0, 1, 2, 3, 4, or 5. 
Options A, C, and D include values that are outside of this range.

Question 16

Match the following. -2 A)number of unpaired electrons in Zn²⁺ B)number of unpaired electrons in Ti²⁺

Accepted Answer

The answer of Match the following.

-2
A)number of unpaired electrons in...

Question 17

Match the following.

-n = 5 to n = 3
A)657 nm
B)7460 nm
C)103 nm
D)1280 nm
E)122 nm

Accepted Answer

The answer of Match the following.

-n = 5 to n...

Question 18

Match the following.

-n = 2 to n = 3
A)657 nm
B)7460 nm
C)103 nm
D)1280 nm
E)122 nm

Accepted Answer

The transition from n=2 to n=3 in the hydrogen atom corresponds to the Balmer series, which is in the visible spectrum. The wavelength for this transition is approximately 657 nm.

Question 19

Match the following.

-n = 6 to n = 5
A)657 nm
B)7460 nm
C)103 nm
D)1280 nm
E)122 nm

Accepted Answer

The answer of Match the following.

-n = 6 to n...

Question 20

Electromagnetic radiation with a wavelength of 531 nm appears as green light to the human eye. The energy of one photon of this light is 3.74 × 10^-19 J. Thus, a laser that emits 1.3 × 10^-2 J of energy in a pulse of light at this wavelength produces ________ photons in each pulse. A)2.9 × 10^-¹⁷ B)9.2 × 10^-24 C)1.8 × 10¹⁹ D)3.5 × 10¹⁶ E)6.5 × 10¹³

Accepted Answer

The answer of Electromagnetic radiation with a wavelength of 531...

Quiz 7: The Quantum-Mechanical Model of the Atom

Match the following. -0

The complete electron configuration of argon, element 18, is ________.

Match the following. -n = 1 to n = 2

How many subshells are there in the shell with n = 4?

Which ion does not have a noble gas configuration in its ground state?

Match the following. -n = 3 to n = 1

Define diffraction.

The element that corresponds to the electron configuration 1s22s22p6 is ________.

The de Broglie wavelength of an electron with a velocity of 6.00 × 106 m s-1 is ________ m. The mass of the electron is 9.11 × 10-28 g.

How many orbitals are there in the fourth shell?

The complete electron configuration of gallium, element 31, is ________.

What are the possible values of n and ml for an electron in a 4d orbital?

For a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy?

For hydrogen, what is the wavelength of the photon emitted when an electron drops from a 4d orbital to a 2p orbital in a hydrogen atom? The Rydberg constant is 1.097 × 10-2 nm-1.

What are the possible values of l if n = 6?

Match the following. -2

Match the following. -n = 5 to n = 3

Match the following. -n = 2 to n = 3

Match the following. -n = 6 to n = 5

Electromagnetic radiation with a wavelength of 531 nm appears as green light to the human eye. The energy of one photon of this light is 3.74 × 10-19 J. Thus, a laser that emits 1.3 × 10-2 J of energy in a pulse of light at this wavelength produces ________ photons in each pulse.

The element that corresponds to the electron configuration 1s²2s²2p⁶ is ________.

The de Broglie wavelength of an electron with a velocity of 6.00 × 10⁶ m s^-1 is ________ m. The mass of the electron is 9.11 × 10^-28 g.

What are the possible values of n and m_l for an electron in a 4d orbital?

For hydrogen, what is the wavelength of the photon emitted when an electron drops from a 4d orbital to a 2p orbital in a hydrogen atom? The Rydberg constant is 1.097 × 10^-2 nm^-1.

Electromagnetic radiation with a wavelength of 531 nm appears as green light to the human eye. The energy of one photon of this light is 3.74 × 10^-19 J. Thus, a laser that emits 1.3 × 10^-2 J of energy in a pulse of light at this wavelength produces ________ photons in each pulse.