How many times will the following function call itself if 5 is passed as the argument?
Void showMessage(int n)
{
$\quad$ If (n > 0)
$\quad$ {
$\quad$ $\quad$ Cout << "Good day!" << endl;
$\quad$ $\quad$ ShowMessage(n - 1) ;
$\quad$ }
}

Question

How many times will the following function call itself if 5 is passed as the argument?
Void showMessage(int n)
{
$\quad$If (n > 0)
$\quad${
$\quad$$\quad$Cout << "Good day!" << endl;
$\quad$$\quad$ShowMessage(n - 1);
$\quad$}
}
A) 1
B) 4
C) 5
D) An infinite number of times

Quizplus · Accepted Answer

The function `showMessage` is a recursive function that calls itself with the argument `n - 1` each time it is invoked, provided `n > 0`. When `5` is passed as the argument, the function will call itself with `n` decremented by `1` each time until `n` becomes `0`, at which point the condition `n > 0` is no longer true, and the recursion stops. This results in a total of `5` calls, including the initial call with `n = 5`.

How Many Times Will the Following Function Call Itself If \quad

How Many Times Will the Following Function Call Itself If $\quad$