Solve the problem.
-The decay of $289 \mathrm{mg}$ of an isotope is given by $A(t)=289 e^{-0.027 t}$, where $t$ is time in years. Find the amount left after 4 years.
A) 259
B) 253
C) 130
D) 281

Name: Solve the problem. -The decay of $289 \mathrm{mg}$ of an isotope is given by $A(t)=289 e^{-0.027 t}$, where $t$ is time in years. Find the amount left after 4 years. A) 259 B) 253 C) 130 D) 281
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Question

Quizplus · Accepted Answer

The amount left after 4 years is $289 e^{-0.027 \times 4} = 259.05 \approx 259$.

Solve the Problem 289mg289 \mathrm{mg}289mg Of an Isotope Is Given By A(t)=289e−0.027tA(t)=289 e^{-0.027 t}A(t)=289e−0.027t

Solve the Problem $289 \mathrm{mg}$ Of an Isotope Is Given By $A(t)=289 e^{-0.027 t}$