Solve the problem.
-The amount of particulate matter left in solution during a filtering process is given by the equation $P(x)=200(2)^{-0.8 n}$, where $n$ is the number of filtering steps. Find the amounts left for $\mathrm{n}=0$ and $\mathrm{n}=5$. (Round to the nearest whole number.)
A) 200,13
B) 400,13
C) 200,6
D) 200,3200

Question

Quizplus · Accepted Answer

For $n=0$, $P(0) = 200(2)^{-0.8 \times 0} = 200(1) = 200$. For $n=5$, $P(5) = 200(2)^{-0.8 \times 5} = 200(2)^{-4} = 200 \times \frac{1}{16} = 12.5$, which rounds to 13.

Solve the Problem P(x)=200(2)−0.8nP(x)=200(2)^{-0.8 n}P(x)=200(2)−0.8n , Where nnn Is the Number of Filtering Steps

Solve the Problem $P(x)=200(2)^{-0.8 n}$ , Where $n$ Is the Number of Filtering Steps