Use the discriminant to determine the number of real solutions of the equation.
-$10-5 a^{2}=-3 a+7$
A) No real solutions
B) 2
C) 1

Name: Use the discriminant to determine the number of real solutions of the equation. -$10-5 a^{2}=-3 a+7$ A) No real solutions B) 2 C) 1
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Question

Quizplus · Accepted Answer

Rearranging the equation gives a quadratic form: $5a^2 - 3a - 3 = 0$. The discriminant $\Delta = b^2 - 4ac$ is calculated as $(-3)^2 - 4(5)(-3) = 9 + 60 = 69$, which is positive, indicating 2 real solutions.

Use the Discriminant to Determine the Number of Real Solutions 10−5a2=−3a+710-5 a^{2}=-3 a+710−5a2=−3a+7

Use the Discriminant to Determine the Number of Real Solutions $10-5 a^{2}=-3 a+7$