Use the discriminant to determine the number of real solutions of the equation.
-$\mathrm{v}^{2}+7 \mathrm{v}-2=0$
A) 1
B) No real solutions
C) 2

Question

Quizplus · Accepted Answer

The discriminant is $b^2-4ac$, where $a$, $b$, and $c$ are the coefficients of the quadratic equation $av^2+bv+c=0$. In this case, $a=1$, $b=7$, and $c=-2$, so the discriminant is:$$7^2-4(1)(-2) = 49+8 = 57$$Since the discriminant is positive, there are two real solutions to the equation.

Use the Discriminant to Determine the Number of Real Solutions v2+7v−2=0\mathrm{v}^{2}+7 \mathrm{v}-2=0v2+7v−2=0

Use the Discriminant to Determine the Number of Real Solutions $\mathrm{v}^{2}+7 \mathrm{v}-2=0$