The displacement (in $\mathrm{cm}$ ) of a point is given by $s=4 t^{3}-3 \sqrt{1+2 t}$. Find the instantaneous velocity and acceleration at $t=1.5 \mathrm{~s}$.

Name: The displacement (in $\mathrm{cm}$ ) of a point is given by $s=4 t^{3}-3 \sqrt{1+2 t}$. Find the instantaneous velocity and acceleration at $t=1.5 \mathrm{~s}$.
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The Answer of The displacement (in $\mathrm{cm}$ ) of a point is given by $s=4 t^{3}-3 \sqrt{1+2 t}$. Find the instantaneous velocity and acceleration at $t=1.5 \mathrm{~s}$.

The Displacement (In cm\mathrm{cm}cm ) of a Point Is Given By s=4t3−31+2ts=4 t^{3}-3 \sqrt{1+2 t}s=4t3−31+2t​

The Displacement (In $\mathrm{cm}$ ) of a Point Is Given By $s=4 t^{3}-3 \sqrt{1+2 t}$