Hooke's Law in physics states that if a spring at rest (equilibrium position ) has a weight attached to it, then the distance the spring stretches is directly proportional to the force (weight).
F = kx
Where F is the force in Newtons(N), x is the distance stretched in meters (m), and k is the spring constant (N/m).
A force of 75 N will stretch the spring 15 cm. How much force to the nearest Newtons is required to stretch the spring 33 cm?
A) 34 N
B) 165 N
C) 37,125 N
D) 2 N

Question

Quizplus · Accepted Answer

Given F = 75 N for x = 15 cm (0.15 m), we find k = F/x = 75/0.15 = 500 N/m. For x = 33 cm (0.33 m), F = kx = 500 * 0.33 = 165 N.

Hooke's Law in Physics States That If a Spring at Rest